在一个等式,这有可能给两个uknown 'ratio表达式通过使用“解决”功能或其他访问?
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方程是
是,可以直接得到“a / c”通过“解决”功能或其他符号功能?
信谊G p p0 r kαY
信谊A B c d
sigma_re = -p0-B * r ^ (- (1 + k));
sigma_thetae = p0 + B / k * r ^ (- (1 + k));
sigma_rp = Y / (alpha -) + * r ^ (k * (alpha -));
sigma_thetapα= Y / (alpha -) + * * r ^ (k * (alpha -));
eqn1 =潜艇(sigma_thetae r c) = =潜艇(sigma_thetap、r、c);
eqn2 =潜艇(sigma_re r c) = =潜艇(sigma_rp、r、c);
[A1 B1] =解决([eqn1 eqn2], [B]);
sigma_re =简化(潜艇(sigma_re B B1),“IgnoreAnalyticConstraints”,真正的)
sigma_thetae =简化(潜艇(sigma_thetae B B1),“IgnoreAnalyticConstraints”,真正的)
sigma_rp =简化(潜艇(sigma_rp, A1),“IgnoreAnalyticConstraints”,真正的)
sigma_thetap =简化(潜艇(sigma_thetap, A1),“IgnoreAnalyticConstraints”,真正的)
sigma_rp_a =简化(潜艇(sigma_rp, r),“IgnoreAnalyticConstraints”,真正的)
eqn3 = sigma_rp_a = = - p
接受的答案
沃尔特·罗伯森
2021年9月11日
信谊A B c d p p0 r kαY G
sigma_re = -p0-B * r ^ (- (1 + k));
sigma_thetae = p0 + B / k * r ^ (- (1 + k));
sigma_rp = Y / (alpha -) + * r ^ (k * (alpha -));
sigma_thetapα= Y / (alpha -) + * * r ^ (k * (alpha -));
eqn1 =潜艇(sigma_thetae r c) = =潜艇(sigma_thetap、r、c);
eqn2 =潜艇(sigma_re r c) = =潜艇(sigma_rp、r、c);
[A1 B1] =解决([eqn1 eqn2], [B]);
sigma_re =简化(潜艇(sigma_re B B1),“IgnoreAnalyticConstraints”,真正的);
sigma_thetae =简化(潜艇(sigma_thetae B B1),“IgnoreAnalyticConstraints”,真正的);
sigma_rp =简化(潜艇(sigma_rp, A1),“IgnoreAnalyticConstraints”,真正的);
sigma_thetap =简化(潜艇(sigma_thetap, A1),“IgnoreAnalyticConstraints”,真正的);
sigma_rp_a =简化(潜艇(sigma_rp, r),“IgnoreAnalyticConstraints”,真正的)
信谊c_a
temp =简化(潜艇(sigma_rp_a c c_a *))
输出=简化(解决(temp = = - p、c_a“IgnoreAnalyticConstraints”,真正的))