Perfect

Just Great

I want to solve routh stability with an unknown K. How can ı do that ?

Wonderfully useful!
Is there a way we could do this symbolically? Like for a parametrized system.

Awesome!!! Thank you so much for this :)

It's helpful!

Works like a charm. Saved me lots of time. Thanks!!!!

How to use it when you need use hurwitz criterion

Awesome, Thank you

Thanks

Great!

enjoy!

thanks a lot

Thank you very much sir!

thx a lot!!!

Great work, btw I would love to know determining Acceptable Gain Values,K? How to change/add the coding?

Thanks a lot

@Leonard Tserrikou
enjoy!

Thanks a lot . It works perfect

Thank you

واقعاً عالی بود داداش ممنون :-)

داداش دمت گرم

داداش دمت گرم

Thankx for sharing great job

Cool. Thanks for sharing.

good job

Cannot deal with special case when all elements in a row is 0. Try [1 0 7 0 5 0 2 0].

good job

ddd

how can i get the criterion with a variable for example , [1 28 356 1952 5248 1000*kc]??

thank you very much for sharing.

sotty ,the code is working good

thanks for the code but it's buggy as mentiond above , try the following vector [1 4 3 12]

The program is buggy and not accurate. Try [1 1 2 24] which is an example of Dorf control text book. Compare your result with this file:
//www.tatmou.com/matlabcentral/fileexchange/25956-routh-hurwitz-stability-test
and compare the result.

very good but how I can operate m-file in command windows
please help me in this
thanks

@ J. Palacio
please explain more ! the result and algorithm both are correct.

@ Azeem A
numbers after precision isn't important , just changing sign of the first column in important.

accurate and works great. only issue is that for larger numbers, it uses scientific notation and as a result some precision is lost.

confusing

the Routh Hurwitz table returns by this algorithm is not the correct one and it uses a very big value of epsilon for one of the special cases.

Very good. And very simple to use. Good job!

This Is The Best At The First!!!

good job and thank u for sharing