Measuring Angle of Intersection

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This example shows how to measure the angle and point of intersection between two beams usingbwtraceboundary, which is a boundary tracing routine. A common task in machine vision applications is hands-free measurement using image acquisition and image processing techniques.

Step 1: Load Image

Read ingantrycrane.pngand draw arrows pointing to two beams of interest. It is an image of a gantry crane used to assemble a bridge.

RGB = imread('gantrycrane.png'); imshow(RGB); text(size(RGB,2),size(RGB,1)+15,'Image courtesy of Jeff Mather',...'FontSize'7'HorizontalAlignment','right'); line([300 328],[85 103],'color',[1 1 0]); line([268 255],[85 140],'color',[1 1 0]); text(150,72,'Measure the angle between these beams','Color','y',...'FontWeight','bold');

Figure contains an axes object. The axes object contains 5 objects of type image, text, line.

Step 2: Extract the Region of Interest

Crop the image to obtain only the beams of the gantry crane chosen earlier. This step will make it easier to extract the edges of the two metal beams.

% you can obtain the coordinates of the rectangular region using% pixel information displayed by imtoolstart_row = 34; start_col = 208; cropRGB = RGB(start_row:163, start_col:400, :); imshow(cropRGB)

Figure contains an axes object. The axes object contains an object of type image.

% Store (X,Y) offsets for later use; subtract 1 so that each offset will% correspond to the last pixel before the region of interestoffsetX = start_col-1; offsetY = start_row-1;

Step 3: Threshold the Image

Convert the image to black and white for subsequent extraction of the edge coordinates usingbwtraceboundaryroutine.

I = rgb2gray(cropRGB); BW = imbinarize(I); BW = ~BW;% complement the image (objects of interest must be white)imshow(BW)

Figure contains an axes object. The axes object contains an object of type image.

Step 4: Find Initial Point on Each Boundary

Thebwtraceboundaryroutine requires that you specify a single point on a boundary. This point is used as the starting location for the boundary tracing process.

提取的边缘低梁, pick a column in the image and inspect it until a transition from a background pixel to the object pixel occurs. Store this location for later use inbwtraceboundaryroutine. Repeat this procedure for the other beam, but this time tracing horizontally.

dim = size(BW);% horizontal beamcol1 = 4; row1 = find(BW(:,col1), 1);% angled beamrow2 = 12; col2 = find(BW(row2,:), 1);

Step 5: Trace the Boundaries

Thebwtraceboundaryroutine is used to extract (X, Y) locations of the boundary points. In order to maximize the accuracy of the angle and point of intersection calculations, it is important to extract as many points belonging to the beam edges as possible. You should determine the number of points experimentally. Since the initial point for the horizontal bar was obtained by scanning from north to south, it is safest to set the initial search step to point towards the outside of the object, i.e. 'North'.

boundary1 = bwtraceboundary(BW, [row1, col1],“N”, 8, 70);% set the search direction to counterclockwise, in order to trace downward.boundary2 = bwtraceboundary(BW, [row2, col2],'E', 8, 90,'counter'); imshow(RGB); holdon;% apply offsets in order to draw in the original imageplot(offsetX+boundary1(:,2),offsetY+boundary1(:,1),'g','LineWidth',2); plot(offsetX+boundary2(:,2),offsetY+boundary2(:,1),'g','LineWidth',2);

Figure contains an axes object. The axes object contains 3 objects of type image, line.

Step 6: Fit Lines to the Boundaries

Although (X,Y) coordinates pairs were obtained in the previous step, not all of the points lie exactly on a line. Which ones should be used to compute the angle and point of intersection? Assuming that all of the acquired points are equally important, fit lines to the boundary pixel locations.

The equation for a line is y = [x 1]*[a; b]. You can solve for parameters 'a' and 'b' in the least-squares sense by usingpolyfit.

ab1 = polyfit(boundary1(:,2), boundary1(:,1), 1); ab2 = polyfit(boundary2(:,2), boundary2(:,1), 1);

Step 7: Find the Angle of Intersection

Use the dot product to find the angle.

vect1 = [1 ab1(1)];% create a vector based on the line equationvect2 = [1 ab2(1)]; dp = dot(vect1, vect2);% compute vector lengthslength1 = sqrt(sum(vect1.^2)); length2 = sqrt(sum(vect2.^2));% obtain the larger angle of intersection in degreesangle = 180-acos(dp/(length1*length2))*180/pi

angle = 129.4971

Step 8: Find the Point of Intersection

Solve the system of two equations in order to obtain (X,Y) coordinates of the intersection point.

intersection = [1 ,-ab1(1); 1, -ab2(1)] \ [ab1(2); ab2(2)];% apply offsets in order to compute the location in the original,% i.e. not cropped, image.intersection = intersection + [offsetY; offsetX]

intersection =2×1143.0917 295.7494

Step 9: Plot the Results.

inter_x = intersection(2); inter_y = intersection(1);% draw an "X" at the point of intersectionplot(inter_x,inter_y,'yx','LineWidth',2); text(inter_x-60, inter_y-30, [sprintf('%1.3f'角),'{\circ}'],...'Color','y','FontSize',14,'FontWeight','bold'); interString = sprintf('(%2.1f,%2.1f)', inter_x, inter_y); text(inter_x-10, inter_y+20, interString,...'Color','y','FontSize',14,'FontWeight','bold');