hello i want to loop this function, anyone can help me? thank you

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Gilang on 29 Jan 2023

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Commented: Luca Ferro on 31 Jan 2023

Accepted Answer: Luca Ferro

mdl1 = fitlm(Xtr1,Ytr1,'quadratic');

mdl2 = fitlm(Xtr2,Ytr2,'quadratic');

mdl3 = fitlm(Xtr3,Ytr3,'quadratic');

mdl4 = fitlm(Xtr4,Ytr4,'quadratic');

mdl5 = fitlm(Xtr5,Ytr5,'quadratic');

mdl6 = fitlm(Xtr6,Ytr6,'quadratic');

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dpb on 29 Jan 2023

Turn the X , Y variables into arrays and then pass to the function by column indices in the loop; save the result as cell array.

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Luca Ferro on 30 Jan 2023

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Xtr=[Xtr1 Xtr2 Xtr3 Xtr4 Xtr5 Xtr6];

Ytr=[Ytr1 Ytr2 Ytr3 Ytr4 Ytr5 Ytr6];

mdl=[];

forjj=1:lenght(Xtr)

mdl (jj) = fitlm (Xtr (jj) Ytr (jj),'quadratic')

end

as said by dpb in the comments.

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dpb on 30 Jan 2023

                                   >> mdl(2)=fitlm(x,y,'linear')
                                  
                                   Errorusing classreg.regr.CompactFitObject/subsasgn (line 228)
                                  
                                   Assignmentusing () is not allowed for a FitObject.
                                  
                                   >>

As the comments also said, the outputs will have to be saved in a cell array as fitlm returns an object.

"Use the curlies, Luke..." :)

                                   ...
                                  
                                   mdl={};
                                  
                                   forjj=1:size(Xtr,2)
                                  
                                   mdl (jj) = fitlm (Xtr (jj) Ytr (jj),'quadratic');
                                  
                                   ...

Also, length is a very dangerous function being defined as

length(X) <-- max(size(X))

Hence, if OP's various x,y arrays have more than six points, X, Y above will return the number of rows in the combined array, not the number of columns; remember, you're taking the size of the overall new array, there, not counting the number of vectors combined to make the array.

Use size with the specific dimension of interest as above or return both arguments and use the one of interest for the given purpose--

                                   [nr,nc]=size(Xtr);% return array size, rows, columns
                                  
                                   fori=1:nc
                                  
                                   ...

Luca Ferro on 31 Jan 2023

oh yeah i'm desolated, didn't check neither knew that ftilm was a matlab function, i thought it was custom made.

I also didn't know about how length has this huge critical aspect, thank you for educating me about it :)

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