Solve DAEs Using Mass Matrix Solvers
用在解微分代数方程e of the mass matrix solvers available in MATLAB®. To use this workflow, first complete steps 1, 2, and 3 fromSolve Differential Algebraic Equations (DAEs). Then, use a mass matrix solver instead ofode15i
.
This example demonstrates the use ofode15s
orode23t
. For details on the other solvers, seeChoose an ODE Solverand adapt the workflow on this page.
Step 1. Convert DAEs to Function Handles
From the output ofreduceDAEIndex
, you have a vector of equationsDAEs
and a vector of variablesDAEvars
. To useode15s
orode23t
, you need two function handles: one representing the mass matrix of a DAE system, and the other representing the right sides of the mass matrix equations. These function handles form the equivalent mass matrix representation of the ODE system whereM(t,y(t))y’(t) =f(t,y(t)).
Find these function handles by usingmassMatrixForm
质量矩阵M
and the right sidesF
.
[M,f] = massMatrixForm(DAEs,DAEvars)
M = [ 0, 0, 0, 0, 0, 0, 0] [ 0, 0, 0, 0, 0, 0, 0] [ 0, 0, 0, 0, 0, 0, 0] [ 0, 0, 0, 0, 0, 0, 0] [ 0, 0, 0, 0, 0, 0, 0] [ 0, 0, 0, 0, -1, 0, 0] [ 0, -1, 0, 0, 0, 0, 0] f = (T(t)*x(t) - m*r*Dxtt(t))/r -(g*m*r - T(t)*y(t) + m*r*Dytt(t))/r r^2 - y(t)^2 - x(t)^2 - 2*Dxt(t)*x(t) - 2*Dyt(t)*y(t) - 2*Dxtt(t)*x(t) - 2*Dytt(t)*y(t) - 2*Dxt(t)^2 - 2*Dyt(t)^2 -Dytt(t) -Dyt(t)
The equations inDAEs
can contain symbolic parameters that are not specified in the vector of variablesDAEvars
. Find these parameters by usingsetdiff
on the output ofsymvar
fromDAEs
andDAEvars
.
pDAEs = symvar(DAEs); pDAEvars = symvar(DAEvars); extraParams = setdiff(pDAEs, pDAEvars)
extraParams = [ g, m, r]
The mass matrixM
does not have these extra parameters. Therefore, convertM
directly to a function handle by usingodeFunction
.
M = odeFunction(M, DAEvars);
Convertf
to a function handle. Specify the extra parameters as additional inputs toodeFunction
.
f = odeFunction(f, DAEvars, g, m, r);
The rest of the workflow is purely numerical. Set parameter values and create the function handle.
g = 9.81; m = 1; r = 1; F = @(t, Y) f(t, Y, g, m, r);
Step 2. Find Initial Conditions
The solvers require initial values for all variables in the function handle. Find initial values that satisfy the equations by using the MATLABdecic
function. Thedecic
accepts guesses (which might not satisfy the equations) for the initial conditions, and tries to find satisfactory initial conditions using those guesses.decic
can fail, in which case you must manually supply consistent initial values for your problem.
First, check the variables inDAEvars
.
DAEvars
DAEvars = x(t) y(t) T(t) Dxt(t) Dyt(t) Dytt(t) Dxtt(t)
Here,Dxt(t)
is the first derivative ofx(t)
,Dytt(t)
is the second derivative ofy(t)
, and so on. There are 7 variables in a7
-by-1
vector. Thus, guesses for initial values of variables and their derivatives must also be7
-by-1
vectors.
Assume the initial angular displacement of the pendulum is 30° orpi/6
, and the origin of the coordinates is at the suspension point of the pendulum. Given that we used a radiusr
of1
, the initial horizontal positionx(t)
isr*sin(pi/6)
. The initial vertical positiony(t)
is-r*cos(pi/6)
. Specify these initial values of the variables in the vectory0est
.
Arbitrarily set the initial values of the remaining variables and their derivatives to0
. These are not good guesses. However, they suffice for our problem. In your problem, ifdecic
errors, then provide better guesses and refer to thedecic
page.
y0est = [r*sin(pi/6); -r*cos(pi/6); 0; 0; 0; 0; 0]; yp0est = zeros(7,1);
Create an option set that contains the mass matrixM
and initial guessesyp0est
, and specifies numerical tolerances for the numerical search.
opt = odeset('Mass', M, 'InitialSlope', yp0est,... 'RelTol', 10.0^(-7), 'AbsTol' , 10.0^(-7));
Find consistent initial values for the variables and their derivatives by using the MATLABdecic
function. The first argument ofdecic
must be a function handle describing the DAE asf(t,y,yp) = f(t,y,y') = 0
. In terms ofM
andF
,这意味着f(t,y,yp) = M(t,y)*yp - F(t,y)
.
implicitDAE = @(t,y,yp) M(t,y)*yp - F(t,y); [y0, yp0] = decic(implicitDAE, 0, y0est, [], yp0est, [], opt)
y0 = 0.4771 -0.8788 -8.6214 0 0.0000 -2.2333 -4.1135 yp0 = 0 0.0000 0 0 -2.2333 0 0
Now create an option set that contains the mass matrixM
of the system and the vectoryp0
of consistent initial values for the derivatives. You will use this option set when solving the system.
opt = odeset(opt, 'InitialSlope', yp0);
Step 3. Solve DAE System
Solve the system integrating over the time span0
≤t
≤0.5
. Add the grid lines and the legend to the plot. The code usesode15s
. Instead, you can useode23s
by replacingode15s
withode23s
.
[tSol,ySol] = ode15s(F, [0, 0.5], y0, opt); plot(tSol,ySol(:,1:origVars),'-o')fork = 1:origVars S{k} = char(DAEvars(k));endlegend(S,'Location','Best') gridon
Solve the system for different parameter values by setting the new value and regenerating the function handle and initial conditions.
Setr
to2
and regenerate the function handle and initial conditions.
r = 2; F = @(t, Y) f(t, Y, g, m, r); y0est = [r*sin(pi/6); -r*cos(pi/6); 0; 0; 0; 0; 0]; implicitDAE = @(t,y,yp) M(t,y)*yp - F(t,y); [y0, yp0] = decic(implicitDAE, 0, y0est, [], yp0est, [], opt); opt = odeset(opt, 'InitialSlope', yp0);
Solve the system for the new parameter value.
[tSol,ySol] = ode15s(F, [0, 0.5], y0, opt); plot(tSol,ySol(:,1:origVars),'-o')fork = 1:origVars S{k} = char(DAEvars(k));endlegend(S,'Location','Best') gridon