Y = sinpi(X)computessin(X*pi)without explicitly computingX*pi. This calculation is more accurate thansin(X*pi)because the floating-point value ofpiis an approximation of π. In particular:
Calculate the sine ofX*piusing the normalsinfunction.
Y = sin(X*pi)
Y =1×50 1.0000 0.0000 -1.0000 -0.0000
The results contain small numerical errors due to the fact thatpiis a floating-point approximation of the true value of. For instance,Y(3)is notexactlyzero even though.
Y(3)
ans = 1.2246e-16
Usesinpito calculate the same values. In this case, the results are exact.
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