$$［\begin{array}{c}{Y}^{”}\\ Cb\\ Cr\end{array}］＝［\begin{array}{c}16.\\ 128.\\ 128.\end{array}］+\alpha \times ［\begin{array}{c}{R}^{”}\\ G^{”}\\ B^{”}\end{array}］$$

$$［\begin{array}{c}{R}^{”}\\ G^{”}\\ B^{”}\end{array}］＝\beta \times （［\begin{array}{c}{Y}^{”}\\ Cb\\ Cr\end{array}］-［\begin{array}{c}16.\\ 128.\\ 128.\end{array}］）$$

$$\text{强度}＝［\begin{array}{ccc}0.299& 0.587& 0.114\end{array}］［\begin{array}{c}{R}^{”}\\ G^{”}\\ B^{”}\end{array}］$$

$$\begin{array}{l}H＝｛\begin{array}{c}（\frac{G^{”}-B^{”}}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& R^{”}＝米\mathrm{一个}X\end{array}& \end{array}\\ （2+\frac{B^{”}-R^{”}}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& G^{”}＝米\mathrm{一个}X\end{array}& \end{array}\\ （4+\frac{R^{”}-G^{”}}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& B^{”}＝米\mathrm{一个}X\end{array}& \end{array}\end{array}\\ \mathrm{年代}＝\frac{米\mathrm{一个}X-米我N}{米\mathrm{一个}X}\\ V＝米\mathrm{一个}X\end{array}$$

$$\begin{array}{l}{H}_{我}＝\lfloor 6H\rfloor \\ f＝6H-H_{我}\\ p＝1-\mathrm{年代}\\ 问＝1-f\mathrm{年代}\\ t＝1-（1-f）\mathrm{年代}\\ \begin{array}{cc}\text{如果}& H_{我}＝0，\begin{array}{cccc}& R_{t米p}＝1，& G_{t米p}＝t，& B_{t米p}＝p\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{我}＝1，\begin{array}{cccc}& R_{t米p}＝问，& G_{t米p}＝1，& B_{t米p}＝p\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{我}＝2，\begin{array}{cccc}& R_{t米p}＝p，& G_{t米p}＝1，& B_{t米p}＝t\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{我}＝3.，\begin{array}{cccc}& R_{t米p}＝p，& G_{t米p}＝问，& B_{t米p}＝1\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{我}＝4，\begin{array}{cccc}& R_{t米p}＝t，& G_{t米p}＝p，& B_{t米p}＝1\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{我}＝5，\begin{array}{cccc}& R_{t米p}＝1，& G_{t米p}＝p，& B_{t米p}＝问\end{array}\end{array}\\ u＝V/\mathrm{马克斯}（R_{t米p}，G_{t米p}，B_{t米p}）\\ R^{”}＝u{R}_{t米p}\\ G^{”}＝u{G}_{t米p}\\ B^{”}＝u{B}_{t米p}\end{array}$$

$$\begin{array}{l}\text{如果}\begin{array}{cc}& {R^{”}}_{\mathrm{年代}RGB}，{G^{”}}_{\mathrm{年代}RGB}，{B^{”}}_{\mathrm{年代}RGB}\le .0.03928\end{array}\\ R_{\mathrm{年代}RGB}＝{R^{”}}_{\mathrm{年代}RGB}/12.92\\ G_{\mathrm{年代}RGB}＝{G^{”}}_{\mathrm{年代}RGB}/12.92\\ B_{\mathrm{年代}RGB}＝{B^{”}}_{\mathrm{年代}RGB}/12.92\\ \text{否则,}\begin{array}{cc}& \begin{array}{cc}\text{如果}& {R^{”}}_{\mathrm{年代}RGB}，{G^{”}}_{\mathrm{年代}RGB}，{B^{”}}_{\mathrm{年代}RGB}>0.03928\end{array}\end{array}\\ R_{\mathrm{年代}RGB}＝{［\raisebox{1ex}{$（{R^{”}}_{\mathrm{年代}RGB}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{\mathrm{2．4}}\\ G_{\mathrm{年代}RGB}＝{［\raisebox{1ex}{$（{G^{”}}_{\mathrm{年代}RGB}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{\mathrm{2．4}}\\ B_{\mathrm{年代}RGB}＝{［\raisebox{1ex}{$（{B^{”}}_{\mathrm{年代}RGB}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{\mathrm{2．4}}\end{array}$$

$$［\begin{array}{c}X\\ Y\\ Z\end{array}］＝［\begin{array}{ccc}0.41239079926596& 0.35758433938388& 0.18048078840183\\ 0.21263900587151& 0.71516867876776& 0.07219231536073\\ 0.01933081871559& 0.11919477979463& 0.95053215224966\end{array}］\times ［\begin{array}{c}{R}_{\mathrm{年代}RGB}\\ G_{\mathrm{年代}RGB}\\ B_{\mathrm{年代}RGB}\end{array}］$$

$$［\begin{array}{c}{R}_{\mathrm{年代}RGB}\\ G_{\mathrm{年代}RGB}\\ B_{\mathrm{年代}RGB}\end{array}］＝{［\begin{array}{ccc}0.41239079926596& 0.35758433938388& 0.18048078840183\\ 0.21263900587151& 0.71516867876776& 0.07219231536073\\ 0.01933081871559& 0.11919477979463& 0.95053215224966\end{array}］}^{-1}\times ［\begin{array}{c}X\\ Y\\ Z\end{array}］$$

$$\begin{array}{l}\text{如果}\begin{array}{cc}& R_{\mathrm{年代}RGB}，G_{\mathrm{年代}RGB}，B_{\mathrm{年代}RGB}\le .0.00304\end{array}\\ {R^{”}}_{\mathrm{年代}RGB}＝12.92R_{\mathrm{年代}RGB}\\ {G^{”}}_{\mathrm{年代}RGB}＝12.92G_{\mathrm{年代}RGB}\\ {B^{”}}_{\mathrm{年代}RGB}＝12.92B_{\mathrm{年代}RGB}\\ \text{否则,}\begin{array}{cc}& \begin{array}{cc}\text{如果}& R_{\mathrm{年代}RGB}，G_{\mathrm{年代}RGB}，B_{\mathrm{年代}RGB}>0.00304\end{array}\end{array}\\ {R^{”}}_{\mathrm{年代}RGB}＝1.055R_{\mathrm{年代}RGB}{}^{（\mathrm{1．0}/\mathrm{2．4}）}-0.055\\ {G^{”}}_{\mathrm{年代}RGB}＝1.055G_{\mathrm{年代}RGB}{}^{（\mathrm{1．0}/\mathrm{2．4}）}-0.055\\ {B^{”}}_{\mathrm{年代}RGB}＝1.055B_{\mathrm{年代}RGB}{}^{（\mathrm{1．0}/\mathrm{2．4}）}-0.055\end{array}$$

$$\begin{array}{l}l＊＝116.{（}^Y-16.，\begin{array}{cc}for& Y/Y_n\end{array}>\mathrm{0.008856.}\\ l＊＝903.3Y/Y_n，\begin{array}{cc}& \text{除此以外}\end{array}\\ \\ \mathrm{一个}＊＝500（f（X/X_n）-f（Y/Y_n））\\ b＊＝200（f（Y/Y_n）-f（Z/Z_n）），\\ \begin{array}{cc}\text{在哪里}& f（t）＝t^{1/3.}\end{array}，\begin{array}{cc}for& t>\mathrm{0.008856.}\end{array}\\ f（t）＝7.787t+16./166.，\begin{array}{cc}& \text{除此以外}\end{array}\end{array}$$

$$\begin{array}{l}\begin{array}{cc}\text{为}& Y/Y_n\end{array}>\mathrm{0.008856.}\\ \\ X＝X_n（P+\mathrm{一个}＊/500{）}^{3.}\\ Y＝Y_n{P}^{3.}\\ Z＝Z_n（P-b＊/200{）}^{3.}，\\ \\ \begin{array}{cc}\text{在哪里}& P＝（l＊+16.）/116.\end{array}\end{array}$$