这是除了代码使用混沌图像加密地图,请帮我知道这段代码是错误的

2 visualizaciones(上月的30二叠纪)

Samaa亚 el 2 de Mayo de 2021

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围绕导演一门pregunta

https://es.mathworks.com/matlabcentral/answers/819845-this-is-apart-from-a-code-for-image-encryption-using-chaotic-map-please-help-me-to-know-what-is-th

Comentada: 为副总经理 el 4 de Mayo de 2021

                         x (1) = 0.2350;
                        
                         y (1) = 0.3500;
                        
                         z (1) = 0.7350;
                        
                         (1)= 0.0125;
                        
                         b (1) = 0.0157;
                        
                         l (1) = 3.7700;
                        
                         image_height = 256;
                        
                         为i = 1:1:70000
                        
                         x (i + 1) = l * x (i) * (1 - x (i)) + b * y (i) * y (i) * x(我)+ * z(我)* z(我)* z(我);
                        
                         y (i + 1) = l * y (i) * (1 y(我))+ b * z (i) * z (i) * y(我)+ * x(我)* x(我)*(我);
                        
                         z (i + 1) = l * z (i) * (1 - z(我))+ b * x (i) * x z (i)(我)* + * y (i) * y(我);
                        
                         结束
                        
                         x =装天花板(mod ((image_height x * 100000)));
                        
                         y =装天花板(mod ((image_height y * 100000)));
                        
                         z =装天花板(mod ((image_height z * 100000)));
                        
                         原始= imread (“peppers.png”);
                        
                         rgb = rgb2gray(原始);
                        
                         (行,坳)= (rgb)大小;
                        
                         n = 500;
                        
                         p = 600;
                        
                         q = 700;
                        
                         为j = 1:1:行
                        
                         k (j) = x (j + n);
                        
                         l (j) = y (j + p);
                        
                         结束
                        
                         % i = 1:1:行
                        
                         % k (i) = x (i + n);
                        
                         %结束
                        
                         % j = 1:1:坳
                        
                         % l (j) = y (j + p);
                        
                         %结束
                        
                         为j = 1:1:坳*行
                        
                         m z (j) = (j + q);
                        
                         结束