评估

x = optimvar (“x”3 2);y = optimvar (“y”、1、2);expr =总和(x, 1) - 2 * y;

xmat = [3, 1;0,1;2,6];sol.x = xmat;sol.y = [4 3];索尔val =评估(expr)

x = optimvar (“x”);y = optimvar (“y”);概率= optimproblem;概率。目标= - x - y / 3;prob.Constraints。cons1 = x + y < = 2;prob.Constraints。cons2 = x + y / 4 < = 1;prob.Constraints。cons3 = x - y < = 2; prob.Constraints.cons4 = x/4 + y >= -1; prob.Constraints.cons5 = x + y >= 1; prob.Constraints.cons6 = -x + y <= 2; sol = solve(prob)

val =评估(prob.Objective sol)