$$为v为＝\sqrt{{\displaystyle \underset{k＝1}{\overset{N}{\sum }}{\left|v_k\right|}^2}}．$$

$${为v为}_p＝{［{\displaystyle \underset{k＝1}{\overset{N}{\sum }}{\left|v_k\right|}^p}］}^{1/p}，$$

$${为X为}_1＝\underset{1\le j\le n}{\mathrm{马克斯}}（{\displaystyle \underset{我＝1}{\overset{米}{\sum }}\left|{\mathrm{一个}}_{我j}\right|}）．$$

$${为X为}_{\infty }＝\underset{1\le 我\le 米}{\mathrm{马克斯}}（{\displaystyle \underset{j＝1}{\overset{n}{\sum }}\left|{\mathrm{一个}}_{我j}\right|}）．$$

$${为X为}_F＝\sqrt{{\displaystyle \underset{我＝1}{\overset{米}{\sum }}{\displaystyle \underset{j＝1}{\overset{n}{\sum }}{\left|{\mathrm{一个}}_{我j}\right|}^2}}}＝\sqrt{\text{痕迹}（X^{\_\_}X）}．$$