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如何专门在数据矩阵中选择列？

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jj on 12 Nov 2011

Commented: Fercho_Salaon 15 Apr 2021

Accepted Answer: Sven

Hello guys,

I know this is a really simple question, which I can't seem to find any answers around on the internet or the help stuffs I've on Matlab.

我上传了一个带有100个数据系列的数据集。但是，我正在尝试只选择特定的列，例如列77到83和第86栏。我如何在Matlab中做到这一点？通常，这将是：

xdatatemp =xdata(:,77:86) - to select columns 77 to 86. But, how do I specifically select col 77 to 83, and col 86?

非常感谢。

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Sven on 12 Nov 2011

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//www.tatmou.com/matlabcentral/answers/21030-how-to-specifically-select-columns-in-a-data-matrix#answer_27739

尝试：

xdatatemp = xdata (: [77:83 86])

And you can even use "end" keywords such as:

xdatatemp = xdata(:,[77:83 86 end end:-1:end-5])

也就是说，当然，如果您希望列77到83，那么86，那么最后一列，那么最后5列向后计数;）

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Fercho_Sala on 15 Apr 2021

@Rik ok, understood... I'm sorry ;)

更多的Answers (2)

珊瑚德马尔瓦尔·罗德里格兹 on 14 May 2020

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//www.tatmou.com/matlabcentral/answers/21030-how-to-pecifically- select-columns-in-a-data-matrix#answer_432493

编辑：珊瑚德马尔瓦尔·罗德里格兹 on 14 May 2020

我有一个各种行和三列的矩阵。一些数据集具有相同的数字。我想把它们放在一起为了改造它。如何按值分隔矩阵？例如，＃1等的所有值都是正确的？

                            1961 1 -11.4
                           
                            1961 2 -12.3.
                           
                            1961 3 -8.2
                           
                            1961 4 -8.6
                           
                            1961 5 -2.4
                           
                            1961年6 7.4
                           
                            1961 7 14.8
                           
                            1961 8 11.1
                           
                            1961 9 5.9
                           
                            1961 10 3.7
                           
                            1961 11 -6.3
                           
                            1961 12 -13.3
                           
                            1962 1 -12.7
                           
                            1962 2 -8.1
                           
                            1962 3 -13
                           
                            1962 4 -1.1
                           
                            1962年5 2.8
                           
                            1962 6 5.9
                           
                            1962 7 12.2
                           
                            1962 8 8.9
                           
                            1962 9 7.2
                           
                            1962 10 -0.1
                           
                            1962 11 -1
                           
                            1962 12 -11

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Rik on 20 Aug 2020

Comment posted as flag by Abdul BasithAshraf:

查找组函数。你通过询问不同的问题来回答。请在将来避免这一点。

prakash patel on 18 May 2020

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编辑：prakash patel on 18 May 2020

a=[12345; 23456; 34567; 45678]

找

i (a)(2.5)

ii colom matrix v=a(;,4)

iii matrx a

iv a(:,2:3)

V SA = A（2：3,2：4）