$$［\begin{array}{c}{Y}^{\prime }\\ Cb\\ Cr\end{array}］＝［\begin{array}{c}16\\ 128\\ 128\end{array}］+{\rm A}\times ［\begin{array}{c}{R}^{\prime }\\ G^{\prime }\\ B^{\prime }\end{array}］$$

$$［\begin{array}{c}{R}^{\prime }\\ G^{\prime }\\ B^{\prime }\end{array}］＝{\rm B}\times （［\begin{array}{c}{Y}^{\prime }\\ Cb\\ Cr\end{array}］-［\begin{array}{c}16\\ 128\\ 128\end{array}］）$$

$$\text{强度}＝［\begin{array}{ccc}0.299& 0.587& 0.114\end{array}］［\begin{array}{c}{R}^{\prime }\\ G^{\prime }\\ B^{\prime }\end{array}］$$

$$\text{强度}＝［\begin{array}{ccc}0.114& 0.587& 0.2999\end{array}］［\begin{array}{c}B＇\\ G^{\prime }\\ R＇\end{array}］$$

$$\begin{array}{l}H＝｛\begin{array}{c}（\frac{G^{\prime }-B^{\prime }}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& R^{\prime }＝米\mathrm{一个}X\end{array}& \end{array}\\ （2+\frac{B^{\prime }-R^{\prime }}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& G^{\prime }＝米\mathrm{一个}X\end{array}& \end{array}\\ （4+\frac{R^{\prime }-G^{\prime }}{米\mathrm{一个}X-米我N}）/6，\begin{array}{cc}\begin{array}{cc}\begin{array}{cc}& \text{如果}\end{array}& B^{\prime }＝米\mathrm{一个}X\end{array}& \end{array}\end{array}\\ \mathrm{年代}＝\frac{米\mathrm{一个}X-米我N}{米\mathrm{一个}X}\\ V＝米\mathrm{一个}X\end{array}$$

$$\begin{array}{l}{H}_{我}＝\lfloor 6H\rfloor \\ f＝6H-H_{我}\\ p＝1-\mathrm{年代}\\ 问＝1-（f＊\mathrm{年代}）\\ t＝1-\mathrm{年代}（1-f）\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝0，\begin{array}{cccc}& R_{\text{tmp}}＝1，& G_{\text{tmp}}＝t，& B_{\text{tmp}}＝p\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝1，\begin{array}{cccc}& R_{\text{tmp}}＝问，& G_{\text{tmp}}＝1，& B_{\text{tmp}}＝p\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝2，\begin{array}{cccc}& R_{\text{tmp}}＝p，& G_{\text{tmp}}＝1，& B_{\text{tmp}}＝t\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝3.，\begin{array}{cccc}& R_{\text{tmp}}＝p，& G_{\text{tmp}}＝问，& B_{\text{tmp}}＝1\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝4，\begin{array}{cccc}& R_{\text{tmp}}＝t，& G_{\text{tmp}}＝p，& B_{\text{tmp}}＝1\end{array}\end{array}\\ \begin{array}{cc}\text{如果}& H_{\text{我}}＝5，\begin{array}{cccc}& R_{\text{tmp}}＝1，& G_{\text{tmp}}＝p，& B_{\text{tmp}}＝问\end{array}\end{array}\\ u＝V/米\\ R^{\prime }＝u＊R_{\text{tmp}}\\ G^{\prime }＝u＊G_{\text{tmp}}\\ B^{\prime }＝u＊B_{\text{tmp}}\end{array}$$

$$\begin{array}{l}{R}_{\text{sRGB}}＝{R^{\prime }}_{\text{sRGB}}/12.92\\ G_{\text{sRGB}}＝{G^{\prime }}_{\text{sRGB}}/12.92\\ B_{\text{sRGB}}＝{B^{\prime }}_{\text{sRGB}}/12.92\end{array}$$

$$\begin{array}{l}{R}_{\text{sRGB}}＝{［\raisebox{1ex}{$（{R^{\prime }}_{\text{sRGB}}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{2.4}\\ G_{\text{sRGB}}＝{［\raisebox{1ex}{$（{G^{\prime }}_{\text{sRGB}}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{2.4}\\ B_{\text{sRGB}}＝{［\raisebox{1ex}{$（{B^{\prime }}_{\text{sRGB}}+0.055）$}\!\left/ \!\raisebox{-1ex}{$1.055$}\right.］}^{2.4}\end{array}$$

$$［\begin{array}{c}X\\ Y\\ Z\end{array}］＝［\begin{array}{ccc}0.41239079926596& 0.35758433938388& 0.18048078840183\\ 0.21263900587151& 0.71516867876776& 0.07219231536073\\ 0.01933081871559& 0.11919477979463& 0.95053215224966\end{array}］\times ［\begin{array}{c}{R}_{\mathrm{年代}RGB}\\ G_{\mathrm{年代}RGB}\\ B_{\mathrm{年代}RGB}\end{array}］$$

$$［\begin{array}{c}{R}_{\mathrm{年代}RGB}\\ G_{\mathrm{年代}RGB}\\ B_{\mathrm{年代}RGB}\end{array}］＝{［\begin{array}{ccc}0.41239079926596& 0.35758433938388& 0.18048078840183\\ 0.21263900587151& 0.71516867876776& 0.07219231536073\\ 0.01933081871559& 0.11919477979463& 0.95053215224966\end{array}］}^{-1}\times ［\begin{array}{c}X\\ Y\\ Z\end{array}］$$

$$\begin{array}{l}{R^{\prime }}_{\text{sRGB}}＝12.92R_{\text{sRGB}}\\ {G^{\prime }}_{\text{sRGB}}＝12.92G_{\text{sRGB}}\\ {B^{\prime }}_{\text{sRGB}}＝12.92B_{\text{sRGB}}\end{array}$$

$$\begin{array}{l}{R^{\prime }}_{\text{sRGB}}＝1.055R_{\text{sRGB}}{}^{（\mathrm{1．0}/2.4）}-0.055\\ {G^{\prime }}_{\text{sRGB}}＝1.055G_{\text{sRGB}}{}^{（\mathrm{1．0}/2.4）}-0.055\\ {B^{\prime }}_{\text{sRGB}}＝1.055B_{\text{sRGB}}{}^{（\mathrm{1．0}/2.4）}-0.055\end{array}$$

$$l^{＊}＝116{（Y/Y_{\text{n}}）}^{1/3.}-16$$

$$l^{＊}＝903.3Y/Y_{\text{n}}$$

$$\begin{array}{l}{\mathrm{一个}}^{＊}＝500（f（X/X_{\text{n}}）-f（Y/Y_{\text{n}}））\\ b^{＊}＝200（f（Y/Y_{\text{n}}）-f（Z/Z_{\text{n}}）），\end{array}$$

$$f（t）＝t^{1/3.}$$

$$f（t）＝7.787t+16/166$$

$$\begin{array}{l}X＝X_{\text{n}}（P+{\mathrm{一个}}^{＊}/500{）}^{3.}\\ Y＝Y_{\text{n}}{P}^{3.}\\ Z＝Z_{\text{n}}（P-b^{＊}/200{）}^{3.}，\end{array}$$

$$P＝（l^{＊}+16）/116$$

$$\begin{array}{l}X＝\raisebox{1ex}{$X_{\text{n}}（（P+\raisebox{1ex}{$\mathrm{一个}$}\!\left/ \!\raisebox{-1ex}{$500$}\right.）-0.138）$}\!\left/ \!\raisebox{-1ex}{$7.787$}\right.\\ Y＝\raisebox{1ex}{$Y_{\text{n}}（P-0.138）$}\!\left/ \!\raisebox{-1ex}{$7.787$}\right.\\ Z＝Z_{\text{n}}（（P-\raisebox{1ex}{$b$}\!\left/ \!\raisebox{-1ex}{$200$}\right.）-0.138）（7.787）\end{array}$$