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难题:重叠的矩形

Posted byDoug Hull,

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Today’s challenge is one where you need to figure out if two rectangles have a non-zero area of overlap.

The rectangles will be specified as follows:

puzzlerrect.jpg

Just fill in your part of the code until you get the binary variable overlap defined.

ax = sort(rand(1,2)); ay = sort(rand(1,2)); bx = sort(rand(1,2)); by = sort(rand(1,2)); clf rectangle('position',[ax(1) ay(1) diff(ax) diff(ay)], 'edgecolor', 'r') hold on rectangle('position',[bx(1) by(1) diff(bx) diff(by)], 'edgecolor', 'k') axis equal %your code here overlap = %1 for overlap, 0 for non-overlapping

When you post your code in the comments, please use the tags

  all the code so someone can just copy and paste it from the comments.

My solution is already posted.

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Topic: Puzzler
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